0,0000038(6,3-x)(10,7-x)^3=x^2

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Solution for 0,0000038(6,3-x)(10,7-x)^3=x^2 equation: 



0.0000038(6.3-x)(10.7-x)^3=x^2

We move all terms to the left:

0.0000038(6.3-x)(10.7-x)^3-(x^2)=0

determiningTheFunctionDomain
-x^2+0.0000038(6.3-x)(10.7-x)^3=0

We add all the numbers together, and all the variables

-x^2+0.0000038(-1x+6.3)(-1x+10.7)^3=0

We add all the numbers together, and all the variables

-1x^2+0.0000038(-1x+6.3)(-1x+10.7)^3=0

We multiply parentheses ..

-1x^2+0.0000038(+x^2-10.7x-6.3x+67.41)^3=0

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